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Graph y=-2 (x+1)^2-1. y = −2(x + 1)2 − 1 y = - 2 ( x + 1) 2 - 1. Find the properties of the given parabola. Tap for more steps... Direction: Opens Down. Vertex: (−1,−1) ( - 1, - 1) Focus: (−1,−9 8) ( - 1, - 9 8) Axis of Symmetry: x = −1 x = - 1. Directrix: y = −7 8 y = - 7 8.Graphing lines calculator. This calculator will plot lines given in following forms: 1.Slope y-intercept form - this is a line of the form where is the slope of the line and is the y-intercept. 2.Standard form - this is the line of the form , where and are real numbers and A and B are both not zero. The calculator will generate a step-by-step ...According to my result, -(4/-2) +(-5) and 4/-2 +(-5) should be the x-coordinates of this graph's y-intersects: -3 and -7, and it checks out! It kind of makes sense as well: we're dividing k - the difference in y from the x-axis at the maximum - by the slope. This should give as result the difference in x from the maximum, and then we're adding ...Microsoft Excel's graphing capabilities includes a variety of ways to display your data. One is the ability to create a chart with different Y-axes on each side of the chart. This ...

Matching of each equation to its graph is: y = x - 2 → Graph 1. y = -2x → Graph 4. x= -2 → Graph 3. y = -2 → Graph 2. How to identify the linear graph? Equation 1 is given as: y = x - 2 . The graph that matches this equation is Graph 1. The 2nd equation is y = -2x. The graph that matches this equation is the 4th graph . The 3rd equation ...See a solution process below: First, solve for two points which solve the equation and plot these points: First Point: For x = 0 y = (1/2 * 0) + 2 y = 0 + 2 y = 2 or (0, 2) Second Point: For x = 2 y = (1/2 * 2) + 2 y = 1 + 2 y = 3 or (2, 3) We can next plot the two points on the coordinate plane: graph{(x^2+(y-2)^2-0.035)((x-2)^2+(y-3)^2-0.035)=0 [-10, 10, -5, 5]} Now, we can draw a straight ...Example 1: drawing linear graphs. Draw the graph of the equation y=3x+1 y = 3x + 1 for all values of x x from -2 −2 to 2. 2. Substitute the. x. \textbf {x} x coordinate into the equation of a straight line. 2 Plot the paired \textbf {x} x and \textbf {y} y coordinates onto the axes. 3 Join the points with a straight line.Rewrite in slope-intercept form. Tap for more steps... y = − 2 3x+1 y = - 2 3 x + 1. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: − 2 3 - 2 3. y-intercept: (0,1) ( 0, 1) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y ...Graph y=(x-1)^2-1. Step 1. Find the properties of the given parabola. Tap for more steps... Step 1.1. Use the vertex form, , to determine the values of , , and . Step 1.2. Since the value of is positive, the parabola opens up. Opens Up. Step 1.3. Find the vertex. Step 1.4. Find , the distance from the vertex to the focus.

Step 3.2.1. Raise to the power of . Step 3.2.2. Divide by . Step 3.2.3. The final answer is . Step 3.3. The value at is . Step 3.4. Replace the variable with in the expression. ... Graph the parabola using its properties and the selected points. Step 4. Graph the parabola using its properties and the selected points. Direction: Opens Up. Vertex:Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history ...Explore math with our beautiful, free online graphing calculator. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more. ….

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Of the three symmetries discussed in Section 1.2.1, only two are of significance to functions: symmetry about the y-axis and symmetry about the origin. 2 Recall that we can test whether the graph of an equation is symmetric about the y-axis by replacing \(\ x\) with \(\ −x\) and checking to see if an equivalent equation results.Trigonometry. Graph y=1/2*e^x. Step 1. Exponential functions have a horizontalasymptote. The equation of the horizontalasymptote is . HorizontalAsymptote: Step 2. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps... x y 0 −2 2 −3 x y 0 - 2 2 - 3. Graph the line using the slope and the y-intercept, or the points. Slope: − 1 2 - 1 2. y-intercept: (0,−2) ( 0, - 2)Graph y=-1/2*sin(3x) Step 1. Use the form to find the variables used to find the amplitude, period, phase shift, and vertical shift. Step 2. Find the amplitude . Amplitude: ... Step 6.5.2.1.2. Subtract full rotations of until the angle is greater than or equal to and less than . Step 6.5.2.1.3. The exact value of is . Step 6.5.2.2.Study with Quizlet and memorize flashcards containing terms like y=x^3, y=1/x^2, y=1/x and more. ... Polar Graphs Equations . 19 terms. skatz25. Preview. Trigonometry derivatives and antiderivative. 18 terms. Eric-_-H. Preview. Trigonometric Derivatives . 12 terms. Charlotte11242004.

dfw radar noaa The MK party, named after the ANC’s former paramilitary wing uMkhonto we Sizwe (meaning “Spear of the Nation”), is currently polling in third at 14.1 percent.We will graph the rational function 1/ x-squared. We will discuss asymptotes, domain and range, and the shifts of the function. can i submit menards rebates onlinechina buffet gaylord mi The X-intercept is the point where the line crosses the x-axis. So, it must be a point on the x-axis. Any point that is on the x-axis will have a y-value of 0. So, you find the x-intercept by using y=0 in the equation and solve for X. You will then have a point (x-value, 0) that is the x-intercept.Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more. Untitled Graph. Save Copy Log InorSign Up. y 4 + x 4 = sin 5 xy. 1 ... pa hs football scores Interactive, free online graphing calculator from GeoGebra: graph functions, plot data, drag sliders, and much more!Explanation: Any linear equation has the form of. #y=mx+b#. #m# is the slope of the equation. #b# is the y-intercept. The slope of the line, #m#, is found by. #m= (y_2-y_1)/ (x_2-x_1)#. where # (x_1,y_1)# and # (x_2,y_2)# are the coordinates of any two points in the line. The y-intercept, #b#, is found by plugging in #x=0# into the equation ... raptor bed liner spraymaaco auto paint costarby's hours open 1.To find the zeros, solve \sqrt {x+3}+1=0. This equation implies \sqrt {x+3}=−1. Since \sqrt {x+3}≥0 for all x, this equation has no solutions, and therefore f has no zeros. 2.The y -intercept is given by (0,f (0))= (0,\sqrt {3}+1). 3.To graph this function, we make a table of values. medishare chat The equation y>5 is a linear inequality equation. y=0x + 5. So whatever we put in for x, we get x*0 which always = 0. So for whatever x we use, y always equals 5. The same thing is true for y>5. y > 0x + 5. And again, no matter what x we use, y is always greater than 5. hinsdale village hallucsc healthbaker's gas and welding supply y-intercept: (0,7) ( 0, 7) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps... x y 0 7 2 8 x y 0 7 2 8. Graph the line using the slope and the y-intercept, or the points. Slope: 1 2 1 2. y-intercept: (0,7) ( 0, 7)